Solving Kinematic Equations 2
A car travels 355 meters in 25 seconds. If it started at rest, find its acceleration.
What is 355 m?
- Δt
- Δx
- a
- vi
- vf
A car travels 355 meters in 25 seconds. If it started at rest, find its acceleration.
Δx = 355 m
What is 25 sec?
- Δt
- Δx
- a
- vi
- vf
A car travels 355 meters in 25 seconds. If it started at rest, find its acceleration.
Δx = 355 m
Δt = 25 sec
What variable is "started at rest"?
- Δt
- Δx
- a
- vi
- vf
A car travels 355 meters in 25 seconds. If it started at rest, find its acceleration.
Δx = 355 m
Δt = 25 sec
vi = 0 m/s
What are you looking for?
- Δt
- Δx
- a
- vi
- vf
A car travels 355 meters in 25 seconds. If it started at rest, find its acceleration.
Δx = 355 m
Δt = 25 sec
vi = 0 m/s
a = ?
Which equation can you use?
- vf = vi + aΔt
- Δx = viΔt + (½)a(Δt)2
- vf2 = vi2 + 2aΔx
- Δx = (½)(vi + vf)Δt